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A river 400m wide is flowing at a rate of 2.0m//s. A boat is sailing at a velocity of 10m//swith respect to the water, in a direction perpendicular to the river.(i) Find the time taken by the boat to reach the opposite bank (ii) How far from the point directly opposite to the starting point does the boat reach the opposite bank (iii) In what direction dies the boat actually move. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a)Time taken to <a href="https://interviewquestions.tuteehub.com/tag/cross-939411" style="font-weight:bold;" target="_blank" title="Click to know more about CROSS">CROSS</a> the river `t= d/V_(y)=(400m)/(10m//s)=40s`<br/>(b)drift `(X)=(v_(x))(t)=(2m//s)(40s)=80m`.<br/> (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) <a href="https://interviewquestions.tuteehub.com/tag/actual-361632" style="font-weight:bold;" target="_blank" title="Click to know more about ACTUAL">ACTUAL</a> direction of boat , `theta=tan^(-1)((10)/2)=tan^(-1)5`, (<a href="https://interviewquestions.tuteehub.com/tag/downstream-959100" style="font-weight:bold;" target="_blank" title="Click to know more about DOWNSTREAM">DOWNSTREAM</a>)with the river flow.</body></html> | |