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A river is flowing due east with a speed `3m//s`. A wimmer can swim in still water at a speed of `4 m//s`. If swimmer starts swimming due north, what will be his resultant velocity (magnitude and direction) ? A. `5 m//s` at `37^(@)` to `N`B. `5 m//s` at `53^(@)` to `N`C. `10 m//s` at `37^(@)` to `N`D. None of these |
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Answer» Correct Answer - A `V_("net") = sqrt((3^(2) + 4^(2))) = 5 m//s` at `tan^(-1) ((3)/(4))` `= 5m//s` at `37^(@)` to N. |
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