A river is flowing due east with a speed 3ms^(-1). A swimmer can swim in still water at a speed of 4ms^(-1). If swimmer starts swimming due north, then the resultant velocity of the swimmer isa) 3 m/sb) 5 m/sc) 7 m/sd) 2 m/s

A river is flowing due east with a speed 3ms^(-1). A swimmer can swim

1.	A river is flowing due east with a speed 3ms^(-1). A swimmer can swim in still water at a speed of 4ms^(-1). If swimmer starts swimming due north, then the resultant velocity of the swimmer isa) 3 m/sb) 5 m/sc) 7 m/sd) 2 m/s
Answer» 3 m `s^(-1)` 5 m `s^(-1)` 7 m `s^(-1)` 2 m `s^(-1)` Solution : Here, Velocity of water FLOWING in river, `vecv_(r) = 3 m s^(-1)` Velocity of swimmer in STILL water, `v_(s) = 4 MS^(-1)` From figure, The resultant velocity of the swimmer is `V = sqrt(v_(s)^(2) + v_(r)^(2)) = sqrt((4)^(2) + (3)^(2)) = sqrt(25) = 5ms^(-1)`