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A river passing near a town floods it on an average twice every 10 years. Assuming Poisson distribution find the probability that the town faces flooding at least once in 10 years. (a) 0.0198(b) 0.1353(c) 0.5657(d) 0.8647 |
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Answer» Correct answer is: (d) 0.8647 P(X ≥ 1) = 1 − P(0) = 1 - \(\cfrac{e^{-2}(2)^\circ}{0!}\) = 1 − e−2 = 0.8647 |
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