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A rocket is launched vertical from the surface of the earth of radius R with an initial speed `v`. If atmospheric resistance is neglected, then maximum height attained by the rocket isA. `h=(R)/(((2gR)/(v^(2))-1))`B. `h=(R)/(((2gR)/(v^(2))+1))`C. `h=(R^(2))/(((2gR)/(v^(2))-1))`D. `h=(R^(2))/(((2gR)/(v^(2))+1))` |
Answer» Correct Answer - A `(1)/(2)mv^(2)=(mgh)/(1+(h)/(R))` On solving Eq. (i) for `h`, we get `:. h=(v^(2))/(2g-(v^(2))/(R))=(R)/(((2gR)/(v^(2)))-1)`. |
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