1.

A rocket is moving with constant acceleration 6. Assume external forces on it to be zero. Exhaust gases escape with velocity u relative to the rocket. Find how its mass changes with time if its initial mass is m_0.

Answer»

Solution :`F = (d)/(dt) (-MU) = -U(dM)/(dt)` ( since u is constant )
`:. M omega = -u (dM)/(dt)` ( where ` omega` is its acceleration )
`(dM)/(M) =(-d omega)/( u)`
Integrating LOG `M=-(omega)/(u)t+C`
when t=0, `M=M_0`
so ` C= log M_0 , log M = -(omega)/(u) t + log M_0 :. log (M)/(M_0) = -(omega)/(u) t`
` (M)/(M_0)=e^((omega)/(u)t) or M = M_0e^((omega)/(u)t)`
Thus , the MASS of the rocket changes exponentially


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