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A rod AB of length l is pivoted at an end A and freely rotated in a horizontal plane at an angular speed omega about a vertical axis passing through A. If coefficient of linear expansion of material of rod is alpha, find the percentagechangein its angular velocity if temperature of system is increased by DeltaT. |
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Answer» Solution :If TEMPERATURE of surroundingincreases by `DeltaT`, the new lengthof rod becomes `l.=l(1+alphaDeltaT)` Due to change in LENGTH, moment of inertia of rod also changes and its is about and end A and is given as `I._(A)= (Ml^(2))/(3)` As no EXTERNALFORCE of torque is actingon rod, its angular momentumremainsconstant during HEATING. Thus we have `I_(A)omega=I_(A).omega.` [where `omega.` is the final anuglarvelocity of rod after heating] (or) `(Ml^(2))/(3)omega=(Ml^(2)(1+alpha DeltaT)^(2))/(3)omega.` `rArr omega=(1+2alpha DeltaT)omega^(1) or omega. = omega(1-2alphaDeltaT)` [using binomialexpansion for small `alpha`] Thus percentagechange in angularvelocity of rod due to heating can be given as `Delta omega=(omega-omega.)/(omega) xx 100%=2alpha DeltaT xx 100%` |
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