1.

A rod of length 2 m and diameter 50 mm is elongated by 5 mm when an axial force. of 400 kN is applied. The modulus of elasticity of the material of the rod will be nearly (a) 66 GPa(b) 72 GPa (c) 82 GPa (d) 96 GPa

Answer»

Correct option is (c) 82 GPa 

Axial elongation, ∆ = \(\cfrac{PL}{AE}\)

E = \(\cfrac{PL}{A∆}\) = \(\cfrac{400\times10^3\times2\times10^3}{\cfrac{\pi}{4}(50)^2\times5}\) = 81.5 GPa



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