1.

A rod of length 2 m and mass 0.5 kg is fixed at one end and allowed to hang vertically from a rigid support. Find the work done in raising the other end of the rod until it makes an angle of 60^(@) with the vertical. (g=10 ms^(-2))

Answer»

SOLUTION :`m=0.5 KG, l=2 m, theta = 60^(@)`
Work done `W=mg.(l)/(2)(1-cos theta)`
`= 0.5xx10xx(2)/(2)(1-cos 60^(@))-5xx(1-(1)/(2))=5xx(1)/(2)=2.5 J`


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