A rod of length 6 m has specific gravity ρ(=25/36). One end of the rod is tied to a 5 m long rope, which in turn is tied to the floor of a pool 10 m deep, as shown. Find the length (in m) of the part of rod which is out of water.

A rod of length 6 m has specific gravity ρ(=25/36). One end of the ro

1.	A rod of length 6 m has specific gravity ρ(=25/36). One end of the rod is tied to a 5 m long rope, which in turn is tied to the floor of a pool 10 m deep, as shown. Find the length (in m) of the part of rod which is out of water.
Answer» A rod of length $6 m$ has specific gravity $ρ (= 25 / 36)$ . One end of the rod is tied to a $5 m$ long rope, which in turn is tied to the floor of a pool $10 m$ deep, as shown. Find the length (in $m$ ) of the part of rod which is out of water.

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A rod of length 6 m has specific gravity ρ(=25/36). One end of the rod is tied to a 5 m long rope, which in turn is tied to the floor of a pool 10 m deep, as shown. Find the length (in m) of the part of rod which is out of water.

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