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A rod of length l, density of material D and area of cross section is A . If it rotates about its axis perpendicular to the length and passing through its centre, then its kinetic energy of rotation will beA. `(Al^(3)omega^(2))/(12)`B. `(Al^(3)D. omega^(2))/(24)`C. `(Al^(3)D. omega^(2))/(6)`D. `(Al^(3)D. omega^(2))/(48)` |
Answer» Correct Answer - B `KE = (1)/(2)I omega^(2)` `= (1)/(2)(ML^(2))/(12)xx omega^(2)` `= (1)/(2)xx(DAL^(3))/(12)omega^(2)` `= (Al^(3)D omega^(2))/(24)` |
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