1.

A rod of mass m and length / is made to stand at an angle of 60^@ with the vertical. Potential energy of the rod in this position is

Answer»

`MGL`
`(mgl)/2`
`(mgl)/3`
`(mgl)/4`

Solution :For any UNIFORM rod, the mass is supposed to be concentrated at its centre.
Height of the mass from ground is
`h = (l//2) sin 30^@`
POTENTIAL energy of the rod
`= MGH xx m xx g xx l/2 sin 30^@`
`= m xx g xx l/2 xx 1/2 = (mgl)/(4)`.


Discussion

No Comment Found