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A rod of mass m and length / is made to stand at an angle of 60^@ with the vertical. Potential energy of the rod in this position is |
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Answer» `MGL` Height of the mass from ground is `h = (l//2) sin 30^@` POTENTIAL energy of the rod `= MGH xx m xx g xx l/2 sin 30^@` `= m xx g xx l/2 xx 1/2 = (mgl)/(4)`.
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