1.

A rod PQ of mass M and length L is hinged at end P. The rod is kept horizontal by a mass less than string tied at a point Q as shown in figure. When string is cut, the initial acceleration rod is:

Answer»

`(3g)/(2L)`
`g/L`
`(2g)/L`
`(2g)/(3L)`

Solution :`tau=I alpha, tau=L/2Mg`
`I=(ML^(2))/3`
`L/2Mg=(ML^(2))/3xxalpha`
`:.alpha=(3g)/(2L)`


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