1.

A roller of diameter 70 cm and length 2 m is rolling on the ground. What is the area covered by the roller in 50 revolutions?

Answer»

Area covered by the roller in 50 revolutions = 50 × Curved surface area of the roller

= 50 x 2 x \(\frac{22}{7}\) x 35 x 200 cm2

= 2200000 cm= 220 m2.



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