A room is 9.68 m long and 6.2 m wide. Its floor is to be covered with

1.	A room is 9.68 m long and 6.2 m wide. Its floor is to be covered with rectangular tiles of size 22 cm by 10 cm. Find the total cost of the tiles at the rate of Rs 2.50 per tile.
Answer» Given length of the floor of the room = 9.68 m Breadth of the floor of the room = 6.2 m We know that area of rectangle = length x breadth Area of the floor = 9.68 m x 6.2 m = 60.016 m² Given that length of the tile = 22 cm Breadth of the tile = 10 cm Area of one tile = 22 cm x 10 cm = 220 cm² = 0.022 m² [Since 1 m² = 10000 c m²] Thus, Number of tiles = 60.016 m²/0.022 m² = 2728 We have cost of one tile = Rs. 2.50 Total cost = Number of tiles x Cost of one tile = (2728 x 2.50) = Rs. 6820

A room is 9.68 m long and 6.2 m wide. Its floor is to be covered with rectangular tiles of size 22 cm by 10 cm. Find the total cost of the tiles at the rate of Rs 2.50 per tile.

Answer»

Given length of the floor of the room = 9.68 m

Breadth of the floor of the room = 6.2 m

We know that area of rectangle = length x breadth

Area of the floor = 9.68 m x 6.2 m

= 60.016 m²

Given that length of the tile = 22 cm

Breadth of the tile = 10 cm

Area of one tile = 22 cm x 10 cm

= 220 cm²

= 0.022 m² [Since 1 m² = 10000 c m²]

Thus, Number of tiles = 60.016 m²/0.022 m²

= 2728

We have cost of one tile = Rs. 2.50

Total cost = Number of tiles x Cost of one tile

= (2728 x 2.50)

= Rs. 6820