A rope ladder of length L is attached to a balloon of mass M. As the man of mass m climbs the ladder into the balloon basket, the balloon comes down by a vertical distance s. Then the increase in potential energy of man divided by the increase in potential energy of balloon is

A rope ladder of length L is attached to a balloon of mass M. As the m

1.	A rope ladder of length L is attached to a balloon of mass M. As the man of mass m climbs the ladder into the balloon basket, the balloon comes down by a vertical distance s. Then the increase in potential energy of man divided by the increase in potential energy of balloon is
Answer» (a) `(L-s)/(s)` (b) `L/s` (c) `(s)/(L-s)` (d) `L-s` Solution :Work done by man, `mgL=mg(L-s)+mgs` where `mg(L-s)` is the INCREASE in potential energy of the man and `mgs` is the increase in potential energy of the BALLOON because the balloon would have been lifted up but for the CLIMBING of the man. So Increase in PE of man/Increase in PE of balloon=`(mg(L-s))/(mgs)-(L-s)/(s)`