A rope of length `((pi)/(2) + 1)` R has been placed on a smooth sphere of radius R as shown in figure. End A of the rope is at the top of the sphere and end B is overhanging. Mass per unit length of the rope is `lambda` . The horizontal string holding this rope in place can tolerate tension equal to weight of the rope. Find the maximum mass `(M_(0))` of a block that can be tied to the end B of the rope so that the string does not break.

A rope of length `((pi)/(2) + 1)` R has been placed on a smooth sphere

1.	A rope of length `((pi)/(2) + 1)` R has been placed on a smooth sphere of radius R as shown in figure. End A of the rope is at the top of the sphere and end B is overhanging. Mass per unit length of the rope is `lambda` . The horizontal string holding this rope in place can tolerate tension equal to weight of the rope. Find the maximum mass `(M_(0))` of a block that can be tied to the end B of the rope so that the string does not break.
Answer» Correct Answer - `M_(0) = lambdaR ((pi)/(2) - 1)`

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