A rotating wheel changes angular speed from 1800 rpm to 3000 rpm in 20 s. What is the angular acceleration assuming to be uniform?

A rotating wheel changes angular speed from 1800 rpm to 3000 rpm in 20

1.	A rotating wheel changes angular speed from 1800 rpm to 3000 rpm in 20 s. What is the angular acceleration assuming to be uniform?
Answer» `2pi rad s^(-2)` `60 pi rad s^(-2)` `40 pi rad s^(-2)` `90 pi rad s^(-2)` Solution :Here , Initial angular speed of the wheel , `omega_(0) = 1800 xx (2pi)/(60) "rad" s^(-1) = 60 pi rad s^-1` Final angular speed of the wheel , `omega= 3000 xx (2pi)/(60) rad s^(-1) = 100 pi rad s^(-1)` Time during which this CHANGE of speed takes PLACE , t = 20 s Let `alpha` be angular acceleration of the wheel . `therefore alpha = (omega - omega_(0)) /(t) = (100 pi - 60 pi)/(20) rad s^(-2) = 2pi rad s^(-2)`