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A rough horizontal plate rotates with angular velocity `omega` about a fixed verticle axis. A particle or mass `m` lies on the plate at a distance `(5a)/(4)` from this axis. The coefficient of friction between the plate and the particle is `(1)/(3)` . The largest value of `omega^(2)` for which the oparticle will continue to be at rest on the revolving plate isA. `(g)/(3a)`B. `(4g)/(5a)`C. `(4g)/(9a)`D. `(4g)/(15a)` |
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Answer» Correct Answer - D `mumg=nRomega^(2)` :. `omega^(2)=(mug)/(R)=((1//3)g)/(5a//4)=(4g)/(15a)` |
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