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    				| 1. | A round table ................. | 
| Answer»   `a/sqrt(2)=R=10` ('a' is the side of SQUARE) `a=10 sqrt(2)` If COM of system is OUTSIDE the square ABCD then table will topple. In the limiting case, taking origin at 'm', `(R-a/2)=(m(0)+MR)/(m+M)` `MXX(R-a/2)=Mxxa/2` `:. m=10/((sqrt(2)-1)) kg` | |