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A round uniform body of radius R, mass M and moment of inertia I rolls down (without slipping) on an inclined plane making an angle theta with the horizontal. Then its acceleration is …………. |
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Answer» `(gsintheta)/(1-(MR^(2))/(I))` `a=(gsintheta)/(1+(K^(2))/(R^(2)))` but for radius of gyration K `I=MK^(2)` `therefore K^(2)=(I)/(M)` `therefore a=(gsintheta)/(1+(I)/(MR^(2)))` |
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