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A roundpebble is releasedfrom the point X inside a frictionless hemisphericalball as shownin the figure suchthatit justuptoedgeYof the bowl . With what speedthe pebbleis releaseddown insidethe bowl? |
Answer» Solution : Let the speed of the pebble when releases from point X inside the bowlis V. Using the law of CONVERSATION of energy , Total energyat X = Total energy at Y ` :. 1/2 mv^(2) +mgd = 0 + mgR ` `rArr ""v^(2) = 2g (R-d) = 2XX 9.8 (0.07 - 0.05)` ` v = 0.626 ` m/s |
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