A Running Train Passes A Pole In 15 Seconds And A Platform Of 100 M L

1.	A Running Train Passes A Pole In 15 Seconds And A Platform Of 100 M Long In 25 Seconds. Find The Length Of The Train?
Answer» Let's suppose TRAIN is RUNNING with a speed of X m/sec having a length of x METERS, so Speed = length/time s= x/15 (while passing a POLE) ........... (i) s= (x+100)/25(while passing the platform)...........( ii) Equating both equations, we get x/15= (x+100)/25 5x=300+3x 2x=300 x=150 meters. Let's suppose train is running with a speed of X m/sec having a length of x meters, so Speed = length/time s= x/15 (while passing a pole) ........... (i) s= (x+100)/25(while passing the platform)...........( ii) Equating both equations, we get x/15= (x+100)/25 5x=300+3x 2x=300 x=150 meters.

A Running Train Passes A Pole In 15 Seconds And A Platform Of 100 M Long In 25 Seconds. Find The Length Of The Train?

Answer»

Let's suppose TRAIN is RUNNING with a speed of X m/sec having a length of x METERS, so

Speed = length/time

s= x/15 (while passing a POLE) ........... (i)

s= (x+100)/25(while passing the platform)...........( ii)

Equating both equations, we get

x/15= (x+100)/25

5x=300+3x

2x=300

x=150 meters.

Let's suppose train is running with a speed of X m/sec having a length of x meters, so

Speed = length/time

s= x/15 (while passing a pole) ........... (i)

s= (x+100)/25(while passing the platform)...........( ii)

Equating both equations, we get

x/15= (x+100)/25

5x=300+3x

2x=300

x=150 meters.

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