A(s)hArrB(g)+C(g) K_(P)=40atm^(2) X(s)hArrB(g)+E(g) Above equilibrium is allowed to attain in a closed container and pressure of B was found to be 10 atm. Calculate standard Gibb's free energy change for X(s)hArrB(g)+E(g) "at" 300K (takeR=2 cal//k//mol)

A(s)hArrB(g)+C(g) K_(P)=40atm^(2) X(s)hArrB(g)+E(g) Above equilibriu

1.	A(s)hArrB(g)+C(g) K_(P)=40atm^(2) X(s)hArrB(g)+E(g) Above equilibrium is allowed to attain in a closed container and pressure of B was found to be 10 atm. Calculate standard Gibb's free energy change for X(s)hArrB(g)+E(g) "at" 300K (takeR=2 cal//k//mol)
Answer» `3.5 Kcal//mol` `3 Kcal//mol` `2.5 Kcal//mol` `2 Kcal//mol` SOLUTION :N//A