A sack contained 45 kg 75 g cement. The mason used 26 kg 598 g orcemen

1.	A sack contained 45 kg 75 g cement. The mason used 26 kg 598 g orcement. How much cement is left in the sack?
Answer» total amount of cement = 45 kg 75 g converting the above quantity into kg75g = (75/1000) = 0.075kgtotal amount of cement = 45+.075 = 45.075kg used cement = 26 kg 598 gconverting the above quantity into kg598g = (588/1000) = 0.598gused cement = 26+.598 = 26.598kg remaining amount of cement= (total amount of cement - used cement)= 45.075 -26.598= 18.477kg amount of cement left in the sack is 18.477kg

A sack contained 45 kg 75 g cement. The mason used 26 kg 598 g orcement. How much cement is left in the sack?

Answer»

total amount of cement = 45 kg 75 g converting the above quantity into kg75g = (75/1000) = 0.075kgtotal amount of cement = 45+.075 = 45.075kg

used cement = 26 kg 598 gconverting the above quantity into kg598g = (588/1000) = 0.598gused cement = 26+.598 = 26.598kg

remaining amount of cement= (total amount of cement - used cement)= 45.075 -26.598= 18.477kg

amount of cement left in the sack is 18.477kg