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A sailor goes 8 kmdownstream in 40 minutes and returns in 1 hours. Determine the speed of thesailor in still water and the speed of the current. |
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Answer» Correct Answer - 10 kmph, 2 kmph Let the speed of the sailor in still water be x kmph and the speed of the current be y kmph. Then, speed downstream = ` (x + y ) ` km/hr. And, speed upstream = ` (x - y ) ` km/hr ` therefore (8)/(x + y ) = ( 40)/(60) = (2)/(3)rArr x + y = 12 " " `… (i) and `(8)/(x - y ) = 1 rArr x - y = 8. " "`… (ii) Solve (i) and (ii). |
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