A sample containing 0.496 gm of (NH_(4))_(2) C_(2)O_(4) (MW = 124) and inert material was dissolved in water and made strongly alkaline with KOH which converts NH_(4)^(+) into NH_(3). The liberated NH_(3) was distilled into exactly 50ml of 0.05M H_(2)SO_(4). The excess H_(2)SO_(4) was back titrated with 10ml of 0.1MNaOH. The percentage of (NH_(4))_(2) C_(2)O_(4) with sample is

A sample containing 0.496 gm of (NH_(4))_(2) C_(2)O_(4) (MW = 124) and

1.	A sample containing 0.496 gm of (NH_(4))_(2) C_(2)O_(4) (MW = 124) and inert material was dissolved in water and made strongly alkaline with KOH which converts NH_(4)^(+) into NH_(3). The liberated NH_(3) was distilled into exactly 50ml of 0.05M H_(2)SO_(4). The excess H_(2)SO_(4) was back titrated with 10ml of 0.1MNaOH. The percentage of (NH_(4))_(2) C_(2)O_(4) with sample is
Answer» <html><body><p>`40%`<br/>`50%`<br/>`60%`<br/>`75%`</p>Solution :m. eqts of <a href="https://interviewquestions.tuteehub.com/tag/excess-978535" style="font-weight:bold;" target="_blank" title="Click to know more about EXCESS">EXCESS</a> `H_(2)SO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) = 10 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 0.1 = 1` <br/> m.eqts of `H_(2)SO_(4)` taken `= 50 xx 0.05 xx 2 = <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>` <br/> m.eqts of `H_(2)SO_(4)` reacted with <br/> `NH_(4) = 4=` m.eqts of `(NH_(4))_(2) C_(2)O_(4)`<br/> wt of `(NH_(4))_(2)C_(2)O_(4) = 4 xx 62 xx 10^(-3)` <br/> % purity `=(4 xx 0.062)/(0.496) xx 100 = 50%`</body></html>