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A sample contains 200 atoms of hydrogen,0.05gm atom of nitrogen,10 raise to -20gm atom of oxygen.what is the approximate no. Of total atoms |
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Answer» 2.1507×10^21 atoms is the correct answer. Explanation: GIVEN data : Number of atoms of hydrogen = 200 No of atom of NITROGEN = 0.05 Number of atom of oxygen = 10^-20 To find The approximate number of total atoms Solution: We know that 14 GRAMS of nitrogen will require 6.022×10²³ atoms Therefore 0.05 grams of nitrogen will require X atoms By cross multiplication, x = 6.022×10²³ × 0.05/ 14 = 2.1507×10²¹ atoms of nitrogen Therefore 0.05 grams of nitrogen will require 2.1507×10²¹ atoms Now we know that, 16 grams of oxygen will require 6.022×10²³ atoms Therefore 10^-20 grams of oxygen will require x atoms By cross multiplication, x = 6.022×10²³ × 10^-20/ 16 = 376.375 atoms Therefore 10^-20 grams of oxygen will require 376.375atoms Now total atoms of compund = atoms of hydrogen+ atoms of nitrogen+ atoms of oxygen = 200+ 2.1507×10²¹ + 376.375 = 2.1507*10^27 atoms Hence, 2.1507×10^21 atoms is the correct answer. |
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