A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. Ammonia evolved was absorbed in 50 mL of 0.5 M H_2SO_4. The residual acid required 60 mL or 0.5 M NaOH solution for neutralisation. Find the percentage composition of nitrogen in the compound.

A sample of 0.50 g of an organic compound was treated according to Kje

1.	A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. Ammonia evolved was absorbed in 50 mL of 0.5 M H_2SO_4. The residual acid required 60 mL or 0.5 M NaOH solution for neutralisation. Find the percentage composition of nitrogen in the compound.
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`50 mL of 0.5 M H_2SO_4 = 50 mL 1N H_2SO_4` <br/> `60 mL 0.5 M NaOH = 60 mL 0.5 N NaoH = 60 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 0.5 = 30 mL 1N NaOH` <br/> `30mL 1N NaOH solution = 30 mL 1N H_2SO_4` <br/> <a href="https://interviewquestions.tuteehub.com/tag/vol-723961" style="font-weight:bold;" target="_blank" title="Click to know more about VOL">VOL</a>. of <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> used up = 50-30 = 20 mL 1N `H_2SO_4` <br/> Percentage `N_2 = (14)/1000 xx (20)/0.5 xx 100 = 5.6%`</body></html>