1.

A sample of 3 bulbs is tested. A bulb is labeled as G if it is good and D if it is defective. Find the number of all possible outcomes.

Answer»

A bulb can be good or defective, so there are 2 different possibilities of a bulb. 

So number of all possible outcomes (of all bulbs) = 2 x 2 x 2 = 8



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