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A sample of a polymer contains 200 molecules of molecular mass `10^(3)` each, 300 molecules of molecular mass `10^(4)` each and 500 molecules each having `10^(5)` as molecular mass. Calculate `bar(M)_(N)` and `bar(M)_(W)` for the sample |
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Answer» `bar(M)_(n)=((200xx10^(3))+(300xx10^(4))+(500xx10^(5)))/(200+300+500)` `=((2+30+500)10^(5))/(1000)=53,200` `bar(M)_(w)=((200xx(10)^(3))^(2)+300xx(10^(4))^(2)+500xx(10^5)^(2))/(200xx10^(3)+300xx10^(4)+500xx10^(5))` `=(10^(8)(2+300+5000))/(10^(5)(2+30+500))=(10^(3)xx50302)/(532)=94,553` |
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