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A sample of clay contains 60% Silica & 15 % water. The sample is heated such that the partially dried sample contains 66% Silica. What will be % of water in partially dries sample ?A. 0.1B. 0.065C. 0.12D. 0.14

Answer» Correct Answer - 2
Support sample is 100 gm
`(W_(si))/(W_("sample"))xx100=66`
`(60xx100)/66=w_("sample")`
`90.9 =w_("sample")`
water left =15-9.1=5.9 gm
% of water `5.9/90.9xx100=6.5%`


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