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A sample of clay contains 60% Silica & 15 % water. The sample is heated such that the partially dried sample contains 66% Silica. What will be % of water in partially dries sample ?A. 0.1B. 0.065C. 0.12D. 0.14 |
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Answer» Correct Answer - 2 Support sample is 100 gm `(W_(si))/(W_("sample"))xx100=66` `(60xx100)/66=w_("sample")` `90.9 =w_("sample")` water left =15-9.1=5.9 gm % of water `5.9/90.9xx100=6.5%` |
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