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A sample of crystalline Ba(OH)_(2). XH_(2)O weight 1.578 gm was dissolved in water. The solution required 40 ml of 0.25 N HNO_(3) for complete relation. Determine the numberof molecular of water of crystallisat in base.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Eqts of `Ba(OH)_(2).xH_(2)O` = <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a> of `HNO_(3)` <br/> `(1.578)/((171+18x)//2)=(<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>)/(1000)xx0.25` <br/> `18x=315.6-171impliesx=8`</body></html>


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