A sample of crystalline Ba(OH)_(2). XH_(2)O weight 1.578 gm was dissolved in water. The solution required 40 ml of 0.25 N HNO_(3) for complete relation. Determine the numberof molecular of water of crystallisat in base.

A sample of crystalline Ba(OH)_(2). XH_(2)O weight 1.578 gm was dissol

1.	A sample of crystalline Ba(OH)_(2). XH_(2)O weight 1.578 gm was dissolved in water. The solution required 40 ml of 0.25 N HNO_(3) for complete relation. Determine the numberof molecular of water of crystallisat in base.
Answer» SOLUTION :Eqts of `Ba(OH)_(2).xH_(2)O` = EQ of `HNO_(3)` `(1.578)/((171+18x)//2)=(40)/(1000)xx0.25` `18x=315.6-171impliesx=8`