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A sample of gas occupies `100 mL` at `27^(@)C` and `740 mm` pressure. When its volume is changed to `80 mL` at `740 mm` pressure, the temperature of the gas will beA. `21.6^(@)C`B. `240^(@)C`C. `-33^(@)C`D. `89.5^(@)C` |
Answer» `V_(1)=100 mL`, `T_(1)=27^(@)C=300 K` `P_(1)=740` `V_(2)= 80mL` `T_(2)=?` `P_(2)=740 mm` `(V_(1))/(T_(1))=(V_(2))/(T_(2))` `:. T_(2)=(V_(2)xxT_(1))/(V_(1))=(80xx300)/(100)=240 K` or `T_(2)= -33^(@)C` |
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