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A sample of helium has a volume of 500 cm3 at 373 K. Calculate the temperature at which the volume will become 260 cm3 . Assume that the pressure is constant. |
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Answer» V1 = 500 cm3 , V2 = 260 cm3 T1 = 373 K, T2 = ? By Charle's Law, \(\frac{V_1}{T_1}=\frac{V_2}{T_2}\) T2 = \(\frac{V_2T_1}{V_1}\) = \(\frac{263\times373}{500}\) = 196.19 K |
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