1.

A sample of `HI(g)` is placed in flask at a pressure of `0.2 atm`. At equilibrium. The partial pressure of `HI(g)` is `0.04 atm`. What is `K_(p)` for the given equilibrium? `2HI(g) hArr H_(2)(g)+I_(2)(g)`

Answer» `pHI =0.04 atm pH_(2) = 0.08 atm , pI_(2) =0.08 atm`
`K_(p) = (pH_(2)xx pI_(2))/(P_(HI)^(2)) =((0.08 atm)xx(0.08 atm))/((0.04 atm)xx(0.04 atm))=4.0`


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