

InterviewSolution
Saved Bookmarks
1. |
A sample of `MgSO_(4)` has `6.023 xx 10^(20)O` atoms What is mass of `Mg` in sample ? . |
Answer» In `MgSO_(4) ("mass of O")/("mass of Mg") = (16 xx 4)/(24) = (8)/(3)` = constant Mass of `6.023 xx 10^(20)` O-atoms `= (6.023 xx 10^(20))/(6.023 xx 10^(23)) xx 16 = 16 xx 10^(-3) gms` `rArr (8)/(3) = (16 xx 10^(-3))/("mass of Mg") rArr` Mass of Mg `= 6 xx 10^(-3)gms` . |
|