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A sample of `MgSO_(4)` has `6.023 xx 10^(20)O` atoms What is mass of `Mg` in sample ? .

Answer» In `MgSO_(4) ("mass of O")/("mass of Mg") = (16 xx 4)/(24) = (8)/(3)` = constant
Mass of `6.023 xx 10^(20)` O-atoms `= (6.023 xx 10^(20))/(6.023 xx 10^(23)) xx 16 = 16 xx 10^(-3) gms`
`rArr (8)/(3) = (16 xx 10^(-3))/("mass of Mg") rArr` Mass of Mg `= 6 xx 10^(-3)gms` .


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