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A sample of nitrogen gas occupies a volume of 1.000 L at a pressure of 0.500 atm at 40ºC. Calculate the pressure if the gas is compressed at 225 cm3 at – 6ºC. |
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Answer» P1 = 0∙500 atm, P2 =? V2 = \(\frac{225}{1000}\) = 0.225 L T1 - 273 + 40 = 313 K T2 = 273 + 6 = 267 K By applying ideal gas equation, \(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\) P2 = \(\frac{P_1V_1\times T_2}{T_1\times V_2}\) = \(\frac{0.500\times 1\times267}{313\times0.225}\) P2 = 1.89 atm |
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