1.

A sample of oleum is such that ratio of free SO_(3) by combined SO_(3) is equal to unity. Calculate its labelling in terms of percentage oleum.

Answer»


Solution :Let FREE `SO_(3)RARR xg`
`SO_(3)` in form of `H_(2)SO_(4)`
`rarr(x)/(80)xx98=1.225x`
so total
`x+1.225x=100`
`x=449.49`
water required `=(44.94)/(80) xx18 = 10..11 G%` oleum `=100+10.11=110.11%`


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