A sample of oleum is such that ratio of free SO_(3) by combined SO_(3) is equal to unity. Calculate its labelling in terms of percentage oleum.

A sample of oleum is such that ratio of free SO_(3) by combined SO_(3)

1.	A sample of oleum is such that ratio of free SO_(3) by combined SO_(3) is equal to unity. Calculate its labelling in terms of percentage oleum.
Answer» <html><body><p><br/></p>Solution :Let <a href="https://interviewquestions.tuteehub.com/tag/free-465311" style="font-weight:bold;" target="_blank" title="Click to know more about FREE">FREE</a> `SO_(3)<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> xg` <br/> `SO_(3)` in form of `H_(2)SO_(4)` <br/> `rarr(x)/(<a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a>)xx98=1.225x` <br/> so total<br/> `x+1.225x=100` <br/> `x=449.49` <br/> water required `=(44.94)/(80) xx18 = 10..11 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>%` oleum `=100+10.11=110.11%` <br/></body></html>