1.

A sample of radioactive element undergoes 90% decomposition in 336 minutes. Its t_(0.5) in minutes is

Answer»

(In 2/l In 10) `xx 366`
1/366
(In 2/1 In 90) `xx 366`
183

Solution :`t_(0.5)=(1)/(LAMBDA)"In" 2, t_(0.9)=(1)/(lambda)"In" 10`
`therefore (t_(0.5))/(t_(0.9))=(ln 2)/(ln 10)`
or `t_(0.5) = ("In"//2//"In" 10)xxt_(0.9)`


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