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A sample of water from a large swimming pool has a resistance of `10000Omega` at `25^(@)C` when placed in a certain conductace cell. When filled with `0.02M KCI` solution, the cell has a resistance of `100 Omega` at `25^(@)C, 585 gm` of `NaCI` were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of `8000 Omega`. Given: Molar conductance of `NaCI` at that concentration is `125 Omega^(-1) cm^(2) mol^(-1)` and molar conductivity of `KCI` at `0.02 M` is `200W^(-1) cm^(2) mol^(-1)`. Cell constant (in `cm^(-1))` of conductane cell is:A. 4B. 0.4C. `4 xx 10^(-2)`D. `4 xx 10^(-5)`

Answer» Correct Answer - B
`k = G xx (l)/(A)`
`^^_(m) =(k xx 1000)/(C) = (200 xx 0.02)/(1000)`
`=(1)/(100) xx (l)/(A) = 0.4 cm^(-10`


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