A satellite is at a height of 25 , 600km from the surface of the earth . If it.s orbital speed is 3.536jkm/s find its time period . (Radius of the earth = 6400 km)

A satellite is at a height of 25 , 600km from the surface of the earth

1.	A satellite is at a height of 25 , 600km from the surface of the earth . If it.s orbital speed is 3.536jkm/s find its time period . (Radius of the earth = 6400 km)
Answer» Solution :`6400KM = 6.4 xx10^(6)m, h = 25` 600 km `=25.6m,v_(0) = 3.536 xx10^(3)m//s` The time PERIOD `T=(2pi(R+h))/V_(0)=(2pi(25.6xx6.4)10^(6))/(3.536xx10^(3))` = `(2pixx32)/(3.536) xx10^(3) = 56,870s`