A satellite is orbiting in an orbit with a velocity 4km/s Then find acceleration due to gravity at that height.

A satellite is orbiting in an orbit with a velocity 4km/s Then find ac

1.	A satellite is orbiting in an orbit with a velocity 4km/s Then find acceleration due to gravity at that height.
Answer» Solution :As centripetal acceleration equal to acceleration DUE GRAVITY at that HEIGHT, then `a = (V^(2))/(r) = g_(h)` and `V^(2) = (GM)/(r) = (GR^(2))/(r)` `rArr r = (gR^(2))/(V^(2)) = (10 xx 6400 xx 6400 xx 10^(6))/(16 xx 10^(6))(g = 10 m//s^(2))` = 25600 km `therefore g_(h) = a = (V^(2))/(r) = (16 xx 10^(6))/(25600 xx 10^(3)) = (10)/(16)m//s^(2)`