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A satellite is orbiting in an orbit witha velocity 4 km/s . Then find acceleration due to gravity at that height. |
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Answer» Solution :As CENTRIPETAL ACCELERATION EQUALS to acceleration due to GRAVITY at thatheight , then `a=V^2/R=g_h` and `V^2=(GM)/r =(gR^2)/r` `rArr r=(gR^2)/V^2=(10xx6400xx6400xx10^6)/(16xx10^6)(g=10m//s^2)` =25600 Km `therefore g_h=a=V^2/r= (16xx10^6)/(25600xx10^3)=10/16m//s^2` |
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