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A satellite is revolving around earth in a circular orbit. At some instant the speed of the satellite is increased `sqrt(2)` times its orbital speed keeping its direction unchanged. Then, the new path of the satellite is :A. circularB. straight lineC. ellipticalD. parabolic |
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Answer» Correct Answer - D The orbital velocity, `v_(0) = sqrt((GM)/(r))` Its velocity is increased by `sqrt(2)` times, new velocity `v =sqrt(2) sqrt((GM)/(r))=sqrt((2GM)/(r))`= escape velocity The path is parabolic in case of escape velocity. |
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