InterviewSolution
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InterviewSolution
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A satellite moves estwards very near the surface of the Earth in equitorial plane with speed `(v_(0))`. Another satellite moves at the same height with the same speed in the equatorial plane but westwards. If `R` =radius of the Earth and `omega` be its angular speed of the Earth about its own axis. Then find the approximate difference in the two time period as observed on the earth.A. `(4piomegaR^(2))/(v_(0)^(2)+R^(2)omega^(2))`B. `(2piomegaR^(2))/(v_(0)^(2)-R^(2)omega^(2))`C. `(4piomegaR^(2))/(v_(0)^(2)-R^(2)omega^(2))`D. `(2piomegaR^(2))/(v_(0)^(2)+R^(2)omega^(2))` |
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Answer» Correct Answer - C `T_(west)=(2piR)/(v_(0)+Romega)` and `T_("east")=(2piR)/(v_(0)-Romega) implies DeltaT=T_("east")` `implies T_("east")-T_(west)=2piR[(2piR)/(v_(0)^(2)-R^(2)omega^(2))]=(4piomegaR^(2))/(v_(0)^(2)-R^(2)omega^(2))` |
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