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A satellite of ....................

Answer»


Solution :`(DA)/(dt)=L/(2m)`
`:. LT=(pi AB)2m`
`L=(2PI abm)/T=(2pim ((r_(a)+r_(p))/2) sqrt(r_(p) r_(a)))/T= (m pi (r_(a)+r_(p)) sqrt(r_(a) r_(p)))/T`


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