1.

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is .........

Answer»

gx
`(GR)/(R-x)`
`(gR^2)/(R+x)`
`((gR^2)/(R+x))^(1/2)`

SOLUTION :`implies` For circular MOTION CENTRIPETAL force = Gravitational force
`(mv_0^2)/(R+x) = (GMm)/((R+x)^2)`
`:. v_0 = sqrt((GM)/(R+x))= sqrt((rR^2)/(R+x))"" [ :. GM = gR^2]`
`:. v_0 = [(gR^2)/(R+x)]^(1/2)`


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