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A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is ......... |
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Answer» gx `(mv_0^2)/(R+x) = (GMm)/((R+x)^2)` `:. v_0 = sqrt((GM)/(R+x))= sqrt((rR^2)/(R+x))"" [ :. GM = gR^2]` `:. v_0 = [(gR^2)/(R+x)]^(1/2)` |
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