A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the gravitationalinfluence of earth? Mass of the satellite is 200 kg, mass of the earth = 6.0 x 10 kg, radius of the earth = 6.4 xx 10^6m, G = 6.67 xx 10^(-11) Nm^2 kg^(-2)

A satellite orbits the earth at a height of 400 km above the surface.

1.	A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the gravitationalinfluence of earth? Mass of the satellite is 200 kg, mass of the earth = 6.0 x 10 kg, radius of the earth = 6.4 xx 10^6m, G = 6.67 xx 10^(-11) Nm^2 kg^(-2)
Answer» SOLUTION : Total energy of ORBITING satellite at a height h ` =- (GMm)/((R+h)) + 1/2 mv^2 = - (GMm)/((R+h)) + 1/2 m (GM)/((R+h)) = (-GMm)/(2(R+h))` Energy expended to rocket the satellite out of the earth.sgravitationalfield. = -(total energy of the satellite) ` = (GMm)/(2(R+h)) = ((6.67 xx 10^(-11)) xx (6 xx 10^24) xx 200)/(2(6.4 xx 10^6 +4 xx 10^5)) = 5.9 xx 10^9 J`