A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the gravitational influence of earth ? Mass of the satellite is 200kg, mass of the earth =6.0 xx10^(24)kgradius of the earth6.4 xx10^(6)m.G = 6.67 xx10^(-11) Nm^(2)kg^(-2).

A satellite orbits the earth at a height of 400 km above the surface.

1.	A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the gravitational influence of earth ? Mass of the satellite is 200kg, mass of the earth =6.0 xx10^(24)kgradius of the earth6.4 xx10^(6)m.G = 6.67 xx10^(-11) Nm^(2)kg^(-2).
Answer» Solution :Total ENERGY of ORBITING satellite at a height `h = (-GMm)/(2(R+h))` Energy expended to rocket the satellite out of the earth .s gravitational field = - (total energy of the satellite) `=(GMm)/(2(R+h))=((6.67xx10^(11))XX(6xx10^(24))xx200)/(2(6.4xx10^(6)+4xx10^(5)))=5.9 xx10^(9)J`